Optimal. Leaf size=273 \[ \frac{a^2 \left (10 a^2 A-25 a b B-18 A b^2\right ) \cot ^3(c+d x)}{30 d}+\frac{a \left (40 a^2 A b+10 a^3 B-55 a b^2 B-28 A b^3\right ) \cot ^2(c+d x)}{20 d}-\frac{\left (-6 a^2 A b^2+a^4 A-4 a^3 b B+4 a b^3 B+A b^4\right ) \cot (c+d x)}{d}+\frac{\left (4 a^3 A b-6 a^2 b^2 B+a^4 B-4 a A b^3+b^4 B\right ) \log (\sin (c+d x))}{d}-x \left (-6 a^2 A b^2+a^4 A-4 a^3 b B+4 a b^3 B+A b^4\right )-\frac{a (5 a B+8 A b) \cot ^4(c+d x) (a+b \tan (c+d x))^2}{20 d}-\frac{a A \cot ^5(c+d x) (a+b \tan (c+d x))^3}{5 d} \]
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Rubi [A] time = 0.732761, antiderivative size = 273, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.226, Rules used = {3605, 3645, 3635, 3628, 3529, 3531, 3475} \[ \frac{a^2 \left (10 a^2 A-25 a b B-18 A b^2\right ) \cot ^3(c+d x)}{30 d}+\frac{a \left (40 a^2 A b+10 a^3 B-55 a b^2 B-28 A b^3\right ) \cot ^2(c+d x)}{20 d}-\frac{\left (-6 a^2 A b^2+a^4 A-4 a^3 b B+4 a b^3 B+A b^4\right ) \cot (c+d x)}{d}+\frac{\left (4 a^3 A b-6 a^2 b^2 B+a^4 B-4 a A b^3+b^4 B\right ) \log (\sin (c+d x))}{d}-x \left (-6 a^2 A b^2+a^4 A-4 a^3 b B+4 a b^3 B+A b^4\right )-\frac{a (5 a B+8 A b) \cot ^4(c+d x) (a+b \tan (c+d x))^2}{20 d}-\frac{a A \cot ^5(c+d x) (a+b \tan (c+d x))^3}{5 d} \]
Antiderivative was successfully verified.
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Rule 3605
Rule 3645
Rule 3635
Rule 3628
Rule 3529
Rule 3531
Rule 3475
Rubi steps
\begin{align*} \int \cot ^6(c+d x) (a+b \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx &=-\frac{a A \cot ^5(c+d x) (a+b \tan (c+d x))^3}{5 d}+\frac{1}{5} \int \cot ^5(c+d x) (a+b \tan (c+d x))^2 \left (a (8 A b+5 a B)-5 \left (a^2 A-A b^2-2 a b B\right ) \tan (c+d x)-b (2 a A-5 b B) \tan ^2(c+d x)\right ) \, dx\\ &=-\frac{a (8 A b+5 a B) \cot ^4(c+d x) (a+b \tan (c+d x))^2}{20 d}-\frac{a A \cot ^5(c+d x) (a+b \tan (c+d x))^3}{5 d}+\frac{1}{20} \int \cot ^4(c+d x) (a+b \tan (c+d x)) \left (-2 a \left (10 a^2 A-18 A b^2-25 a b B\right )-20 \left (3 a^2 A b-A b^3+a^3 B-3 a b^2 B\right ) \tan (c+d x)-2 b \left (12 a A b+5 a^2 B-10 b^2 B\right ) \tan ^2(c+d x)\right ) \, dx\\ &=\frac{a^2 \left (10 a^2 A-18 A b^2-25 a b B\right ) \cot ^3(c+d x)}{30 d}-\frac{a (8 A b+5 a B) \cot ^4(c+d x) (a+b \tan (c+d x))^2}{20 d}-\frac{a A \cot ^5(c+d x) (a+b \tan (c+d x))^3}{5 d}+\frac{1}{20} \int \cot ^3(c+d x) \left (-2 a \left (40 a^2 A b-28 A b^3+10 a^3 B-55 a b^2 B\right )+20 \left (a^4 A-6 a^2 A b^2+A b^4-4 a^3 b B+4 a b^3 B\right ) \tan (c+d x)-2 b^2 \left (12 a A b+5 a^2 B-10 b^2 B\right ) \tan ^2(c+d x)\right ) \, dx\\ &=\frac{a \left (40 a^2 A b-28 A b^3+10 a^3 B-55 a b^2 B\right ) \cot ^2(c+d x)}{20 d}+\frac{a^2 \left (10 a^2 A-18 A b^2-25 a b B\right ) \cot ^3(c+d x)}{30 d}-\frac{a (8 A b+5 a B) \cot ^4(c+d x) (a+b \tan (c+d x))^2}{20 d}-\frac{a A \cot ^5(c+d x) (a+b \tan (c+d x))^3}{5 d}+\frac{1}{20} \int \cot ^2(c+d x) \left (20 \left (a^4 A-6 a^2 A b^2+A b^4-4 a^3 b B+4 a b^3 B\right )+20 \left (4 a^3 A b-4 a A b^3+a^4 B-6 a^2 b^2 B+b^4 B\right ) \tan (c+d x)\right ) \, dx\\ &=-\frac{\left (a^4 A-6 a^2 A b^2+A b^4-4 a^3 b B+4 a b^3 B\right ) \cot (c+d x)}{d}+\frac{a \left (40 a^2 A b-28 A b^3+10 a^3 B-55 a b^2 B\right ) \cot ^2(c+d x)}{20 d}+\frac{a^2 \left (10 a^2 A-18 A b^2-25 a b B\right ) \cot ^3(c+d x)}{30 d}-\frac{a (8 A b+5 a B) \cot ^4(c+d x) (a+b \tan (c+d x))^2}{20 d}-\frac{a A \cot ^5(c+d x) (a+b \tan (c+d x))^3}{5 d}+\frac{1}{20} \int \cot (c+d x) \left (20 \left (4 a^3 A b-4 a A b^3+a^4 B-6 a^2 b^2 B+b^4 B\right )-20 \left (a^4 A-6 a^2 A b^2+A b^4-4 a^3 b B+4 a b^3 B\right ) \tan (c+d x)\right ) \, dx\\ &=-\left (a^4 A-6 a^2 A b^2+A b^4-4 a^3 b B+4 a b^3 B\right ) x-\frac{\left (a^4 A-6 a^2 A b^2+A b^4-4 a^3 b B+4 a b^3 B\right ) \cot (c+d x)}{d}+\frac{a \left (40 a^2 A b-28 A b^3+10 a^3 B-55 a b^2 B\right ) \cot ^2(c+d x)}{20 d}+\frac{a^2 \left (10 a^2 A-18 A b^2-25 a b B\right ) \cot ^3(c+d x)}{30 d}-\frac{a (8 A b+5 a B) \cot ^4(c+d x) (a+b \tan (c+d x))^2}{20 d}-\frac{a A \cot ^5(c+d x) (a+b \tan (c+d x))^3}{5 d}+\left (4 a^3 A b-4 a A b^3+a^4 B-6 a^2 b^2 B+b^4 B\right ) \int \cot (c+d x) \, dx\\ &=-\left (a^4 A-6 a^2 A b^2+A b^4-4 a^3 b B+4 a b^3 B\right ) x-\frac{\left (a^4 A-6 a^2 A b^2+A b^4-4 a^3 b B+4 a b^3 B\right ) \cot (c+d x)}{d}+\frac{a \left (40 a^2 A b-28 A b^3+10 a^3 B-55 a b^2 B\right ) \cot ^2(c+d x)}{20 d}+\frac{a^2 \left (10 a^2 A-18 A b^2-25 a b B\right ) \cot ^3(c+d x)}{30 d}+\frac{\left (4 a^3 A b-4 a A b^3+a^4 B-6 a^2 b^2 B+b^4 B\right ) \log (\sin (c+d x))}{d}-\frac{a (8 A b+5 a B) \cot ^4(c+d x) (a+b \tan (c+d x))^2}{20 d}-\frac{a A \cot ^5(c+d x) (a+b \tan (c+d x))^3}{5 d}\\ \end{align*}
Mathematica [C] time = 1.56371, size = 257, normalized size = 0.94 \[ \frac{20 a^2 \left (a^2 A-4 a b B-6 A b^2\right ) \cot ^3(c+d x)+30 a \left (4 a^2 A b+a^3 B-6 a b^2 B-4 A b^3\right ) \cot ^2(c+d x)-60 \left (-6 a^2 A b^2+a^4 A-4 a^3 b B+4 a b^3 B+A b^4\right ) \cot (c+d x)+60 \left (4 a^3 A b-6 a^2 b^2 B+a^4 B-4 a A b^3+b^4 B\right ) \log (\tan (c+d x))-15 a^3 (a B+4 A b) \cot ^4(c+d x)-12 a^4 A \cot ^5(c+d x)+30 i (a+i b)^4 (A+i B) \log (-\tan (c+d x)+i)-30 (a-i b)^4 (B+i A) \log (\tan (c+d x)+i)}{60 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.098, size = 440, normalized size = 1.6 \begin{align*} -{\frac{A\cot \left ( dx+c \right ){b}^{4}}{d}}+{\frac{B{b}^{4}\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}}-A{a}^{4}x+4\,{\frac{A{a}^{3}b\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}}-4\,{\frac{Ba{b}^{3}c}{d}}-A{b}^{4}x+6\,{\frac{A{a}^{2}{b}^{2}c}{d}}+4\,{\frac{B{a}^{3}bc}{d}}-4\,{\frac{Aa{b}^{3}\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}}-2\,{\frac{Aa{b}^{3} \left ( \cot \left ( dx+c \right ) \right ) ^{2}}{d}}-4\,{\frac{B\cot \left ( dx+c \right ) a{b}^{3}}{d}}-2\,{\frac{A{a}^{2}{b}^{2} \left ( \cot \left ( dx+c \right ) \right ) ^{3}}{d}}-3\,{\frac{B{a}^{2}{b}^{2} \left ( \cot \left ( dx+c \right ) \right ) ^{2}}{d}}-{\frac{A{a}^{3}b \left ( \cot \left ( dx+c \right ) \right ) ^{4}}{d}}-{\frac{4\,B{a}^{3}b \left ( \cot \left ( dx+c \right ) \right ) ^{3}}{3\,d}}-{\frac{A{a}^{4} \left ( \cot \left ( dx+c \right ) \right ) ^{5}}{5\,d}}-{\frac{B{a}^{4} \left ( \cot \left ( dx+c \right ) \right ) ^{4}}{4\,d}}-{\frac{A\cot \left ( dx+c \right ){a}^{4}}{d}}+{\frac{B{a}^{4}\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}}+{\frac{A{a}^{4} \left ( \cot \left ( dx+c \right ) \right ) ^{3}}{3\,d}}+{\frac{B{a}^{4} \left ( \cot \left ( dx+c \right ) \right ) ^{2}}{2\,d}}-{\frac{A{b}^{4}c}{d}}-4\,Ba{b}^{3}x+6\,A{a}^{2}{b}^{2}x+4\,B{a}^{3}bx+6\,{\frac{A\cot \left ( dx+c \right ){a}^{2}{b}^{2}}{d}}-6\,{\frac{B{a}^{2}{b}^{2}\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}}+2\,{\frac{A{a}^{3}b \left ( \cot \left ( dx+c \right ) \right ) ^{2}}{d}}+4\,{\frac{B\cot \left ( dx+c \right ){a}^{3}b}{d}}-{\frac{A{a}^{4}c}{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.46627, size = 390, normalized size = 1.43 \begin{align*} -\frac{60 \,{\left (A a^{4} - 4 \, B a^{3} b - 6 \, A a^{2} b^{2} + 4 \, B a b^{3} + A b^{4}\right )}{\left (d x + c\right )} + 30 \,{\left (B a^{4} + 4 \, A a^{3} b - 6 \, B a^{2} b^{2} - 4 \, A a b^{3} + B b^{4}\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right ) - 60 \,{\left (B a^{4} + 4 \, A a^{3} b - 6 \, B a^{2} b^{2} - 4 \, A a b^{3} + B b^{4}\right )} \log \left (\tan \left (d x + c\right )\right ) + \frac{12 \, A a^{4} + 60 \,{\left (A a^{4} - 4 \, B a^{3} b - 6 \, A a^{2} b^{2} + 4 \, B a b^{3} + A b^{4}\right )} \tan \left (d x + c\right )^{4} - 30 \,{\left (B a^{4} + 4 \, A a^{3} b - 6 \, B a^{2} b^{2} - 4 \, A a b^{3}\right )} \tan \left (d x + c\right )^{3} - 20 \,{\left (A a^{4} - 4 \, B a^{3} b - 6 \, A a^{2} b^{2}\right )} \tan \left (d x + c\right )^{2} + 15 \,{\left (B a^{4} + 4 \, A a^{3} b\right )} \tan \left (d x + c\right )}{\tan \left (d x + c\right )^{5}}}{60 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.83649, size = 695, normalized size = 2.55 \begin{align*} \frac{30 \,{\left (B a^{4} + 4 \, A a^{3} b - 6 \, B a^{2} b^{2} - 4 \, A a b^{3} + B b^{4}\right )} \log \left (\frac{\tan \left (d x + c\right )^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) \tan \left (d x + c\right )^{5} + 15 \,{\left (3 \, B a^{4} + 12 \, A a^{3} b - 12 \, B a^{2} b^{2} - 8 \, A a b^{3} - 4 \,{\left (A a^{4} - 4 \, B a^{3} b - 6 \, A a^{2} b^{2} + 4 \, B a b^{3} + A b^{4}\right )} d x\right )} \tan \left (d x + c\right )^{5} - 12 \, A a^{4} - 60 \,{\left (A a^{4} - 4 \, B a^{3} b - 6 \, A a^{2} b^{2} + 4 \, B a b^{3} + A b^{4}\right )} \tan \left (d x + c\right )^{4} + 30 \,{\left (B a^{4} + 4 \, A a^{3} b - 6 \, B a^{2} b^{2} - 4 \, A a b^{3}\right )} \tan \left (d x + c\right )^{3} + 20 \,{\left (A a^{4} - 4 \, B a^{3} b - 6 \, A a^{2} b^{2}\right )} \tan \left (d x + c\right )^{2} - 15 \,{\left (B a^{4} + 4 \, A a^{3} b\right )} \tan \left (d x + c\right )}{60 \, d \tan \left (d x + c\right )^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 2.92577, size = 1030, normalized size = 3.77 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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